tlhIngan-Hol Archive: Tue Jul 07 12:03:57 1998
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numbers (Re: Question from a newbie)
- From: TPO <[email protected]>
- Subject: numbers (Re: Question from a newbie)
- Date: Tue, 7 Jul 1998 15:03:51 -0400
>> '(2 x 10^2) + (3 x 10^1) + (4 x 10^0)'. Zero is absolutely necessary in
>> place-holder notation, to hold the place of powers of the base without
>> a value: '101' = '(1 x 10^2) + (0 x 10^1) + (1 x 10^0)'.
>> ... Counting proceeded as follows: 1, 2, 3, 3+1, 3+2, 3+3;
>> 2x3+1, 2x3+2, 2x3+3; 3x3+1; 3x3+2; 3x3+3; and then it got complicated." 8+)
>>
>Then 1x9+1x3+1, 1x9+1x3+2, etc.
What Terrence wrote for the base ten is the same idea...
number ABC = (A x 3^2) + (B x 3^1) + (C x 3^0)
* same as = (A x 9) + (B x 3) + (C x 1)
number ABCD = (A x 3^3) + (B x 3^2) + (C x 3^1) + (D x 3^0)
* same as = (A x 27) + (B x 9) + (C x 3) + (D x 1)
DloraH