tlhIngan-Hol Archive: Wed May 17 18:00:54 2000
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Re: chay Doch Do maghmeH tlhIngan Hol lo'lu'?
- From: [email protected]
- Subject: Re: chay Doch Do maghmeH tlhIngan Hol lo'lu'?
- Date: Wed, 17 May 2000 21:00:08 -0400 (EDT)
Voragh:
> Hoch lup 300 qelI'qam leng nughoSbogh Duj.
> "Each second the ship approaching us travels 300 kellicams."
maj! Much better. Can this be extended to any other x/y quantity?
/HIqvaD Hoch tlho'ren 3 DeQ DaDIlnIS/
"For the ale, you need to pay 3 credits per klorn."
> Hoch lup latlh 300 qelI'qam leng nughoSbogh Duj.
> The approaching ship is accelerating at 300 kellicams per second per second.
> ("Each second the ship approaching us travels an additional 300 kellicams.")
I don't think that works. It still sounds like it's talking about
velocity here. When your acceleration is, say, 300 k/s^2, you are not
just travelling an "additional" 300 k per second; you are adding an
additional 300 k/s to your velocity, per second. After, say, 3 seconds,
your velocity has increased by 900 k/s, and so you travel an additional
900+ k in that second than you would if you hadn't been accelerating.
How about:
/Hoch lup, Hoch lup 300 qelI'qam chung nughoSbogh Duj/
"The ship is accelerating towards us at 300 k per second, per second."
What we need is a way to say, "squared". Do we know how to do
exponents in Klingon? (I imagine that math terminology is on
the wish list already.)
Would /cha'logh/ work?
/cha'logh Hoch lup, 300 qelI'qam chung nughoSbogh Duj/
Nah, sounds too much like it's accelerating twice at 300 k/s.
De'vID:
> : The reason that I replaced the /'oH/ is, what does it stand for in
> : the above? It doesn't stand for /wejvatlh qelI'qammey/, because
> : the velocity is 300 k *per second*, not just 300 k. qar'a'?
Voragh:
> I'm not sure I understand the question. In tuv'el's example the
> pronoun-as-verb {'oH} refers to {Do}, the subject of the 2nd sentence:
>
> qaStaHvIS wa' lup, wejvatlh qelI'qammey 'oH Do'e'.
> "During one second, the velocity is 300 kellicams."
Right. When you have /B 'oH A'e'/, you're saying "A is B".
The above sentence says "During 1 second, the *velocity* is
300 k" - but the *velocity* isn't 300 k, the *distance* is
300 k. Unless the /'oH/ refers to /qaStaHvIS wa' lup,
wejvatlh qelI'qammey/, "300 k, during 1 second"? Can
/'oH/ refer to a sentence like that? Intinct says no, but
I could be mistaken. ('ach Duj tIvoqtaH, qar'a'?)
--
De'vID
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